Using methods inside a function

Question

Hello! I'm trying to make a slider for the player, but the problem is that when I create an audio object, I can't call a method inside a function and have to call setInterval twice. Tell me, please, can I somehow fix this?

That is, you have to do this:

 var audio = new Audio(); setInterval("var a = Math.floor(audio.currentTime / (audio.duration / 200))", 500); setInterval(function(){ $('#timeline').css({"width" : "" + a + "px"}); }, 500);

Instead of doing this:

 var audio = new Audio(); setInterval(function(){ var a = Math.floor(audio.currentTime / (audio.duration / 200)); $('#timeline').css({"width" : "" + a + "px"}); }, 500);

what a meaningful title of the question ... but oh well, why doesn't the second code actually work for you?
))) I thought that probably you can not use the methods of objects that were created outside of the function

Deleted 351 one five 13 · Answer 1 · 2012-08-11T20:38:20

And if you do this (so that in one circuit it was):

 (function(){ var audio = new Audio(); setInterval(function(){ var a = Math.floor(audio.currentTime / (audio.duration / 200)); $('#timeline').css({"width" : "" + a + "px"}); }, 500); }());

Using methods inside a function

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