Array in function

Question

Interested in new_select(..., массив) , what's wrong with the array? The function does not work with it at all. If you remove it and substitute a number for it, for example, it will work. new_select('sel1', 2)

 function new_select(id, obj) { array_s = obj; array_int = document.getElementById(id); for(i = 1; i <= array_s.length; i++) { var array_value = array_s[i][1]; var array_text = array_s[i][2]; } array_int.innerHTML = '\ <div class="select">\ <div id="t'+id+'" class="select_title">Выберите тип</div>\ <div id="s'+id+'" class="selector">\ <div class="selector_img"></div>\ </div>\ <div id="l'+id+'" class="select_list">\ ad <br />asdasd <br> asd <br />\ </div>\ </div>'; var summ_width = $('#t'+id).width() + $('#s'+id).width() + 63; $('#l'+id).css('width', summ_width); } new_select('sel1', [[0, 'Выберите тип'], [1, 'Один'], [2, 'Два']]);

With an array, everything is fine, look for problems in the function.

stck stck 4,452 9 26 · Answer 1 · 2012-10-09T13:01:31

See the exclamation marks in the code above. Incorrect indexing you get. Arrays are indexed with 0 and accordingly the last index will be array-1. And the rest is nothing supernatural. Do you use the framework? It is not clear why, at first, then you set document.getElementById (id); when you can $ ('#' + id). After all, they return the same thing - an element.

 function new_select(id, obj) { array_s = obj; array_int = document.getElementById(id); for(i = /*!*/0; i <= array_s.length-1/*!*/; i++) { var array_value = array_s[i][1]; var array_text = array_s[i][2]; } array_int.innerHTML = '\ <div class="select">\ <div id="t'+id+'" class="select_title">Выберите тип</div>\ <div id="s'+id+'" class="selector">\ <div class="selector_img"></div>\ </div>\ <div id="l'+id+'" class="select_list">\ ad <br />asdasd <br> asd <br />\ </div>\ </div>'; var summ_width = $('#t'+id).width() + $('#s'+id).width() + 63; $('#l'+id).css('width', summ_width); }

ModaL ModaL 2,606 five 42 112 · Accepted Answer · 2012-10-09T12:57:05

Problem solved. The error was in the loop. It was necessary to write this:

 i < array_s.length;

not like this:

 i <= array_s.length;

It should be like this: for (i = 0; i <array_s.length; i ++) and not mud kneading: for (i = 1; i <array_s.length; i ++) {

Array in function

2 answers 2

More articles: