The function of highlighting links in the text. Help with google.com view

Question

There is a function that highlights the links in the text. Links like: http://google.com and www.google.ru stand out successfully, but google.ru is not highlighted. That is, you need a third regular expression for replacing links like google.ru

function link_it($text) { // преобразование текста в ссылку $text = preg_replace('/(http:\/\/([\w\d\.\?\&\#\;\:\+\-\=\%\/]+))/i', '<a href="$1">$1</a>', $text); $text = preg_replace('/(www.([a-zA-Z_0-9\.\?\&\#\;\:\+\-\=\%\/]*))/i', '<a href="http://$1">$1</a>', $text); return($text); }

Accepted Answer · 2012-11-25T13:59:02

Try it:

 /(([az]+:\/\/)?(?:[a-zа-я0-9@:_-]+\.)+[a-zа-я0-9]{2,4}(?(2)|\/).*?)([-.,:]?(?:\\s|\$))/is

Includes:
- all imaginable and not conceivable protocols, as well as their absence.
- any number of subdomains.
- Cyrillic in the name of the site, which is relevant in our time for the Russian Federation.
- the link ends in a space or where the end of the line.
- the link must contain a slash, otherwise, besides google.ru, the expression will catch system.time.getLocalTime ()
Using:

 $text=<<<HEREDOC http://Google.com/test Google.com Google.com/test http://Google.com HEREDOC; echo preg_replace("/(([az]+:\/\/)?(?:[a-zа-я0-9@:_-]+\.)+[a-zа-я0-9]{2,4}(?(2)|\/).*?)([-.,:]?(?:\\s|\$))/is",'<b>$1</b>$3', $text);

Result:

http://Google.com/test
Google.com
Google.com/test
http://Google.com

but after all in real life no one writes a slash at the end of the link, right?
so it is necessary to catch, apparently, according to the list of TLDs.
Usually they write :) Most links do not lead to the root of the site, but to some page.
If without a slash, then a protocol is necessary then otherwise it will find any words written together through a period.
Complicate this expression a little later and update the answer.

The function of highlighting links in the text. Help with google.com view

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