What the function returns

Question

function check_login($login, $pass) { return ($_POST['login'] == 'root') && ($_POST['pass'] == '123321'); }

Correctly, I understand that this function returns true / false depending on the username / password match? I don't understand what the abbreviated ifs syntax is ..

Accepted Answer · 2012-12-15T22:46:10

Think for yourself. The comparison itself returns true or false by itself, right?

Let's go further. The first part is true if and only if login was root, right? And the second - if the pass was 123321. That is, everything together will be true if the login root, and pass 123321. And of course false otherwise.

You see that no if are needed.

That is, in principle, the function could be rewritten with if 's, in a more familiar way, like this:

 function check_login($login, $pass) { $result = ($_POST['login'] == 'root') && ($_POST['pass'] == '123321'); if ($result == true) { return true; } else { return false; } }

Or so:

 function check_login($login, $pass) { $result = ($_POST['login'] == 'root') && ($_POST['pass'] == '123321'); if ($result == true) { return $result; } else { return $result; } }

But why?

I saw a shortened version of the conditional operator, but it was a little different from what I remember
A boolean expression can not only be “fed” in if , it is in principle no different from a number, for example.
You do not see problems in the return 3 + 5; code return 3 + 5;
@sof_ka: on the contrary, for me the code is if (expr) {return true;
it seems redundant: after all, in any case, we return exactly what the value of our expr , so why check it once again?

What the function returns

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