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1 answer
Let a pointer to an array be given:
int *array;
Then for the array of dimension [lxwxh] the element at the position (a, b, c) will be accessible by the offset
element = *(array + a * (w * h) + b * (h) + c)
Or through dereference:
int array[l][w][h]; element = *( *( *(array + a) + b) + c)
- I have a task. work with matrices C = 2 (A + B) * B below is a program. I was given the task (1) to find the product of negative matrix elements using a subroutine that returns a value. 2) Access to the matrix matrix as instructed.) Can you fix the code, eh? - Vital
- five@Vital: money for the project in half? - VladD
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