<?php $p = "vopros1"; ?>
  • 2
    $ p = "vopros9"; What should be next? $ p = "vopros0"; Then what is after him? $ p = "vopros1"; Or after $ p = "vopros9": $ p = "vopros10"; Then it may be worth asking the question as follows: >> How to make a variable counter, in which the first part is a string, and the second is incremented? Then the answer will be something like this: $ constPart = 'vopros'; $ numPart = 1; $ p = $ constPart + $ numPart; // $ p = 'vopros1'; .... $ numPart ++; $ p = $ constPart + $ numPart; // $ p = 'vopros2'; .... - BOPOH
  • Or "vopros1" you get from somewhere? And you need to increase not the last character (read the number), but the last number? In general - is it possible to describe the problem in more detail, so that you can give a more or less adequate answer? - BOPOH

4 answers 4

 $p = "vopros1"; echo substr_replace($p,substr($p,-1) + 1, -1); // vopros2 
     <?php const WHILE_COUNT = 10; $count = NULL; $p = 'vopros'; while ($count<=WHILE_COUNT) { ++$count; printf ("%s%s <br>\n",$p,$count); } ?> 
       $p = "vopros1"; $p = preg_replace_callback('/\d+/', function($m) { return ++$m[0]; }, $p);

      PHP 5.3+

        <? php const WHILE_COUNT = 10; $ count = NULL;

        $ p = 'vopros';

        while ($ count <= WHILE_COUNT) {++ $ count; $ p = 'vopros'. $ count;
        echo $ p; }?>

        It's so much easier for mine ... :) Or do you want to increase the variable by redirecting the page, then you need either a cookie or a session ....