Link 2 arrays

Question

Hello, I've been puzzling for half a day, I can't connect all 2 arrays of a parent and a child. there are arrays

Parent

[0] => Array ( [id] => 15 [title] => Название )

Child

  [0] => Array ( [id] => 1 [parent] => 15 ) [1] => Array ( [id] => 2 [parent] => 15 )

How to add the [child] key with the contents of the $ child array to the $ parent array, taking into account that $ parent ['id'] should be equal to $ child ['parent']

From this example, it should be so

  [0] => Array ( [id] => 15 [title] => Название [child] => Array ( [0] => Array ( [id] => 1 [parent] => 15 ) [1] => Array ( [id] => 2 [parent] => 15 ) ) )

I did not quite understand what should happen in the end :) Can you give an example, directly on the data from the question?
Do you need to be in a structure (ie, initially set this way) or programmatically (so that after executing the code from 2 arrays, the necessary array is obtained)?
@eicto, using $ parent [0] ['child'] = $ child you do not guarantee that only elements whose parent is a given element will be added to the child parent.
Besides, if you need to implement this scheme for several parents?
After all, parent is specified as an array, which means that besides the first element there can be a second one.

BOPOH BOPOH 4,594 2 gold marks 20 silver marks 48 bronze marks · Accepted Answer · 2013-03-13T13:25:41

 foreach ($parent as &$parentElement) { $parentElement['child'] = array(); foreach ($child as &$childElement) { if ($childElement['parent'] != $parentElement['id']) { continue; } $parentElement['child'][] = $childElement; } }

Solves the problem, although I do not like here that we are driving the child array back and forth.

You can do differently:

 $result = array(); foreach ($parent as &$parentElement) { $parentId = $parentElement['id']; $result["$parentId"] = array( 'parent' => $parentElement, 'child' => array(), ); } foreach ($child as &$childElement) { $parentId = $childElement['parent']; if (!isset($result["$parentId"])) { continue; } $result["$parentId"]['child'][] = $childElement; }

Thus, we obtain an array consisting of a set of elements (parent and child array). It is not so convenient to use it, but we make far fewer passes during construction.

If necessary, you can get the source array from the last example. But this again - extra gestures.

And yet - the goal was to build an associative array, so I use "$ parentId" in the keys. It will work or not - I don’t know, it’s laziness to check, although in theory it should work out normally, not like with numbers.

Your second option works correctly, except for the fact that the Child key is created to a higher level, and the Child key should be created next to id, please look at the title of my post, where the original picture should turn out.
Changed the penultimate construction to $ result ["$ parentId"] ['products_id'] ['child'] [] = $ childElement;
So the point is that in the second version, not exactly the array is created, which is needed, but it is created (with larger sizes of the original arrays) much faster than in the first variant.
Comrade @ReinRaus, by the way, was a little ahead of me in this.
His version and my first option - in fact there is one and the same.
Converting my second version to your desired form is easy: $ newResult = array ();
foreach ($ result as $ values) {$ parent = $ values ['parent'];
$ parent ['child'] = $ values ['child'] $ newResult [] = $ parent;
But I don't like the fact that we are going through the cycle again.
Or to alter a little logic - you can create two methods - getParent and getChild, and when you loop through the array received in the second variant, call them.

Answer 2 · 2013-03-13T13:25:09

 $parent['child']=Array(); foreach ($child as $k=>$v) if ($v['parent']==$parent['id']) $parent['child'][]=$v;

ReinRaus

16k 3 gold marks 32 silver marks 77 bronze marks

Can I have the full version? After all, your construction needs to be wrapped in a loop, because where do you get $ parent ['id']? - dogmar
I thought you needed an algorithm, but it turned out you need a snippet. Sorry. - ReinRaus
If I choose between the algorithm and the snippet, of course I will choose a snippet, I don’t have time at work :) I’d be at home .. I’ll go back to your lines of the algorithm :) - dogmar

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Link 2 arrays

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