I spread the code. For some reason, the radio buttons do not transmit values ​​to the database. Tell me what the problem is.

if (empty($_POST)) { ?> <form action="invite.php" method="post"> <b>Электронная почта&nbsp;</b><br /> </div> <input type="text" name="login" /></div> <b>Пароль</b></div> <input type="password" name="password" /> </div> Еда <input type="radio" value="j" name="food"> <input type="radio" value="d" name="food"> </div> Не еда <input type="radio" name="nofoot" value="2"> </div> <input type="submit" value="Готово" > </div> </form> <?php } else { $login = (isset($_POST['login'])) ? mysql_real_escape_string($_POST['login']) : ''; $password = (isset($_POST['password'])) ? mysql_real_escape_string($_POST['password']) : ''; $nofood = (isset($_POST['nofood'])) ? mysql_real_escape_string($_POST['nofood']) : ''; $food = (isset($_POST['food'])) ? mysql_real_escape_string($_POST['food']) : ''; $error = false; $errort = ''; if (strlen($login) < 2) { $error = true; $errort .= 'Вы не указали ваш e-mail'; } if (strlen($password) < 6) { $error = true; $errort .= 'Пароль должен быть не меннее 6 символов'; } $query = "SELECT `id` FROM `users` WHERE `login`='{$login}' LIMIT 1"; $sql = mysql_query($query) or die(mysql_error()); if (mysql_num_rows($sql)==1) { $error = true; $errort .= 'В базе уже есть эта почта.Укажите другую.'; } if (!$error) { $salt = GenerateSalt(); $hashed_password = md5(md5($password) . $salt); $query = "INSERT INTO `users` SET `login`='{$login}', `city`='{$city}', `password`='{$hashed_password}', `salt`='{$salt}'"; $sql = mysql_query($query) or die(mysql_error()); print '<h4>Поздравляем, Вы успешно зарегистрированы!</h4><a href="login.php">Авторизоваться</a>'; } else { print '<h4>Возникли следующие ошибки</h4>' . $errort; } }

    1 answer 1

    Try to specify the same names for the buttons, but only with different values.

     Еда:<input type="radio" value="yfood" name="food"> Не еда:<input type="radio" value="nfood" name="food"> .... $food = (isset($_POST['food']) ? mysql_real_escape_string($_POST['food']) : ""; ... mysql_insert("INSERT INTO `users` SET `food` = '".$food."' ");

    Anyway, I didn’t notice in your code that the data from $ food were transferred to the database