How can I get 4 days 3 hours 45 minutes from 4.46875?
I get the answer in this form, I need to convert to the number of days, hours, minutes ...

  • Is it from Excel or what? There, the time in this format is stored - look at the @VladD algorithm below. True, 0.46 - cannot correspond to 3.45 hours ... - Barmaley
  • @Gorets: another example: ideone.com/ki29ui - VladD
  • 2
    attention correct answer: no way, because we can only guess what each number means. Although one option is: if (input.equals ("4.46875")) return "4 days 3 hours 45 minutes"; - jmu
  • @jmu: if it comes to that, then just return "4 дня 3 часа 45 минут"; , about the other values ​​of the argument says nothing . - VladD

2 answers 2

For example :

 double rawDays = 4.46875; int days = (int)Math.floor(rawDays); double rawRestHours = (rawDays - days) * 24; int hours = (int)Math.floor(rawRestHours); double rawRestMinutes = (rawRestHours - hours) * 60; int minutes = (int)Math.floor(rawRestMinutes); double restSeconds = (rawRestMinutes - minutes) * 60;

PS: In Java 8 there will be a data type representing a time period.

  • are you serious? such a way in java? - Gorets 6:01 pm
  • @Gorets: Is there a better option? (without using Joda Time) - VladD
  • one
    @Gorets: Not so wrong. Calendar represents a point in time, not a period . Therefore, there may be fun, for example, during the transition to summer time or there in leap years. (If our time period is several years long.) - VladD
  • one
    @VladD floor(0.46875*24)=11 hours - as it does not walk out ... - Barmaley
  • one
    @Barmaley: why not dance? 4.46 days is a little less than 4 and a half days, half a day is just 12 hours. - VladD
 System.out.println(String.format( "%1$te дня %1$tH час(а/ов) %1$tM минут(а/ы)", new GregorianCalendar(0, 0, 0, 0, 0, (int) (4.46875 * 24 * 3600))));