Where does setTimeout go (setInterval)

Question

A therapeutic «дебаунцер» so that the hover does NOT work too abruptly:

 $('p').text('Заработала страничка, сделай hover меня'); $('p').hover( function () { k=setInterval(show_tip('div'),2000); // <- почему нет задержки 2 сек?? }, function () { hide_tip('div'); }); function show_tip(target) {$(target).fadeIn(300);} function hide_tip(target) {clearInterval(k); $(target).fadeOut(300);}

But setInterval does not want to save me, can you save (but not for the bijou freelancers)?
Oh yes, the same fiddle: http://jsfiddle.net/alpha9000/B93bL/

Accepted Answer · 2013-09-02T22:35:50

@ Oleg B , because the argument for setTimeout and setInterval is a function and not undefined like yours :)

hint: show_tip('div') will be executed immediately, because the script will try to calculate the argument for the setInterval function) (yesterday I answered exactly the same question)

why don't you write in hover for some reason?

 $('p').hover( k=setInterval(show_tip('div'),2000); // <- почему нет задержки 2 сек?? , hide_tip('div'); );

Here and in setInterval , it is also necessary to give the argument a function, not its result.

The link should be beaten http://hashcode.ru/questions/<qid>#<aid>
I just can’t get used to the fact that js is there instead of just a link ...
@eicto, everything would be fine, but only I have this there, and the construction is k = setInterval (function () {show_tip (this);}, 3000);
Already as I understand it passes another this, mb there are some options?
here is approximately how here: jsfiddle.net/alpha9000/nGaHh although I found the option: $ ('p'). hover (function () {mytarget = this; setTimeout (function () {show_tip (mytarget);}, 600); }, function () {hide_tip (this);});
here you got mytarget into the global context without var .

Where does setTimeout go (setInterval)

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