Preg_split puzzle - who can solve?

Question

Based on the previous question

How to make a variant with // ?

It works incorrectly:

 $str = 'a/b/c/d/e//f/g/h//i'; $arr = preg_split('~(?<!/)/~',$str);

The answer should be such

 a b c d e//f g h//i

A little thought, I wrote this code:

 $str = 'a/b/c/d/e//f/g/h//i'; $arr = preg_split('/(?<!\/)\/(?!\/)/',$str);

Answer:

 Array ( [0] => a [1] => b [2] => c [3] => d [4] => e//f [5] => g [6] => h//i )

At first glance, it works correctly, but if there are a lot of //// symbols, then there are no:

 $str = 'a/b/c/d/e////f/g/h//i'; $arr = preg_split('/(?<!\/)\/(?!\/)/',$str);

The answer should be:

 Array ( [0] => a [1] => b [2] => c [3] => d [4] => e [5] => // [6] => f [7] => g [8] => h//i )

How to fix? @Deonis

Something like: / (? <! \ /) \ / (?! \ / (?: \ / \ /) *)) / It is not clear how to divide: e /// fe ///// f
For your options, [you can try this] [1]: $ arr = preg_split ('# (? <! [Az] \ /) \ / (? = [Az] | \ / {3}) #', $ str );
But I agree with @ReinRaus - what to do if there are an odd number of slashes in a row or there will be a couple of them?

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