Output the generated numbers

Question

There is a function that generates 4 numbers and displays them separated by commas. For example, 13, 15, 1, 8,. How can I remove the last comma?

function random($min, $max) { for ($i = 0; $i < 4; $i++) { echo mt_rand($min, $max) . ", "; } }

Aleks G Aleks G 467 4 silver marks 14 bronze marks · Accepted Answer · 2015-06-16T14:29:43

There are several options, for example, to collect all the numbers, then display them:

 function random($min, $max) { $values = array(); for ($i=0; $i<4; $i++){ array_push($values, mt_rand($min, $max)); } echo implode(', ', $values); }

Answer 2 · 2015-06-16T16:13:35

Could be so : )

 function random($min, $max) { printf( '%d, %d, %d, %d', mt_rand($min, $max), mt_rand($min, $max), mt_rand($min, $max), mt_rand($min, $max) ); }

Rostislav Vasilenko Rostislav Vasilenko 57 5 bronze marks · Answer 3 · 2015-06-16T14:41:44

As an option: Generate 3 numbers, and 4 without a comma

KeyGenQt KeyGenQt 182 7 bronze marks · Answer 4 · 2015-06-17T01:00:49

 function random($min, $max) { for ($i = 0; $i < 4; $i++) { echo mt_rand($min, $max) . ($i < 3 ? ',' : ''); } }

fori1ton 22.2k 3 gold marks 38 silver marks 64 bronze marks · Answer 5 · 2015-06-16T14:40:37

Just cut the last character:

 function random($min, $max) { for ($i=0; $i<4; $i++){ $a .= mt_rand($min, $max).", "; } echo substr($a, 0, -1); }

5 answers 5