Actually the question: you need to PHP to count the number of files in the folder. Correction: read only files, excluding subfolders.

    5 answers 5

    For example:

    $dir = opendir('path/to/dir'); $count = 0; while($file = readdir($dir)){ if($file == '.' || $file == '..' || is_dir('path/to/dir' . $file)){ continue; } $count++; } echo 'Количество файлов: ' . $count;
    • $ file is the name of the file. extension, so you can filter on the desired type. - Dem
    • unless he considers only files, but not files and folders? - knes
    • Sorry, added check on the folder - Dem
    • '.' and '..' are also folders, i.e. verification is superfluous. There is another question - is it correct to consider links, sockets, etc. as files. On sh in * nix I would write if [-f $ file]; then cnt = expr $cnt + 1 fi - avp

    I think you can make it even easier.

     echo count(scandir('/folder/'));
    • "scandir - Get a list of files and directories" - from php.net. Only files can not be selected - Dem
    • Pass the array through the additional filter, that's the whole problem. - Arni
    • If there are a lot of files and folders in the folder, the version with scandir too resource-intensive, unlike opendir - Hit-or-miss

    Taken from here https://stackoverflow.com/questions/12801370/count-how-many-files-in-directory-php

     $fi = new FilesystemIterator("/path/to/folder", FilesystemIterator::SKIP_DOTS); printf("Всего файлов: %d", iterator_count($fi));
    • Considering that the issue has already started for the eighth year, your reaction rate is not very high. - freim
    • I now have a broader task: count the number of files, their sizes, the date of the oldest and the newest, so I myself used iteration based on the results of glob(rtrim($path, '/') . '/*', GLOB_NOSORT) - Sergey Beloglazov
    • Below, @ustatos provided interesting statistics that show exactly what filesystemIterator provides for the fastest result. Now I went to the console, subjectively, 'ls' was executed instantly, 'ls -l' 0.5-1 c on a couple of dozen files. Apparently, receiving file attributes is quite a long operation - Sergey Beloglazov
     $cfiles = count(array_diff(scandir("/path/to/folder"), [".", ".."])); printf("Всего файлов: %d", $cfiles);
    • Please give a brief explanation of the code. - 0xdb

    Another option with an iterator and some statistics

     While: 0.42448782920837 FilesystemIterator 0.0074279308319092 DirectoryIterator: 0.77696204185486 echo countFile(__DIR__); function countFile($dir) { $iterator = new DirectoryIterator($dir); $count = 0; iterator_apply( $iterator, 'isFile', [$iterator, &$count] ); return $count; } function isFile(Iterator $item, int &$count) { if ($item->isFile()) { $count++; } return true; }