Photo output by php file name

Question

There is a folder with a photo ./img/mega_foto_2/

This folder contains images:

acura_ilx_endurance_racer_2013_1.jpg acura_ilx_endurance_racer_2013_2.jpg acura_ilx_endurance_racer_2013_3.jpg acura_ilx_endurance_racer_2013_4.jpg ....... acura_nsx_2016_1.jpg acura_nsx_2016_2.jpg acura_nsx_2016_3.jpg acura_nsx_2016_4.jpg alfa_romeo_giulia_2016_1.jpg alfa_romeo_giulia_2016_2.jpg alfa_romeo_giulia_2016_3.jpg alfa_romeo_giulia_2016_4.jpg alfa_romeo_pandion_concept_2010_1.jpg alfa_romeo_pandion_concept_2010_2.jpg alfa_romeo_pandion_concept_2010_3.jpg alfa_romeo_pandion_concept_2010_4.jpg

For example, the file is called acura_ilx_endurance_racer_2013.php

How to make a conclusion on the file name? For example, if the file is acura_ilx_endurance_racer_2013.php, then output only a photo with the name acura_ilx_endurance_racer_2013_1.jpg, acura_ilx_endurance_racer_2013_2.jpg ..... acura_ilx_endurance_racer_2013_n.jpg

  <?php $directory = './img/mega_foto_2'; //название папки с изображениями $allowed_types=array('jpg','jpeg'); //разрешеные типы изображений $file_parts=array(); $ext=''; $title=''; $i=0; //пробуем открыть папку $dir_handle = @opendir($directory) or die("There is an error with your image directory!"); // имя файла PHP $php_filename = basename($_SERVER['PHP_SELF']); // обрежем `.php` $php_filename = substr($php_filename, 0, -4); $counter = 0; //заводим счетчик for($i=0; $i<=(sizeof($php_filename)-1); $i++) { $files=array(); while ($file = readdir($dir_handle)) //поиск по файлам { if($file=='.' || $file == '..') continue; array_push($files,$file); } sort($files); $stop = 3; foreach ($files as $file) { if (($srch = strripos($file, $php_filename)) !== FALSE) { echo '<div id="container"><img src="js/blank.gif" data-src="'.$directory.'/'.$file.'" /></div>'; --$stop; } $counter++; //увеличиваем счетчик на единичку } // если найдена третья картинка, то стоп if (!$stop) { break; } $i++; } closedir($dir_handle); //закрыть папку ?> <?php echo $counter; ?>

If I understand your question correctly, you can try the following method.
Using the explode function, explode break them into two parts: to the point and after the point.
The part that is after the point is discarded, and the first part is written to the variable separately for the file and the picture.
Then compare the occurrence of the file name in the picture name using the stripos function.
It turns out that the name of the image contains the corresponding file name, and if a match is found, then continue.
The stripos function returns the position of the first occurrence of a substring case-insensitive.
That is, if we compare the lines acura_ilx_endurance_racer_2013 and acura_ilx_endurance_racer_2013_1, then it will find the first line in the second and return 0 in this case, which means - a match is found from position 0.

toxxxa toxxxa 1,093 five nineteen · Accepted Answer · 2015-09-02T06:19:42

 $images = array( 'acura_ilx_endurance_racer_2013_1.jpg', 'acura_ilx_endurance_racer_2013_2.jpg', 'acura_ilx_endurance_racer_2013_3.jpg', 'acura_ilx_endurance_racer_2013_4.jpg' ); // имя файла PHP $php_filename = basename($_SERVER['PHP_SELF']); // обрежем `.php` $php_filename = substr($php_filename, 0, -4); // искать третее вхождение нужно не по имени, а по порядку $stop = 3; foreach ($images as &$image) { // искать подстроку в строке if (($srch = strripos($image, $php_filename)) !== FALSE) { echo "<img src='$image'>\n"; --$stop; } // если найдена третья картинка, то стоп if (!$stop) { break; } } unset($image);

Constantly output happens: img_1.jpg, img_10.jpg, but should img_1.jpg, img_2.jpg ... Why is this happening?
Used instead of sort function natcasesort - solution to this problem
if everything worked out, correct the original question message.
so that a visitor who comes by chance here can figure out what was discussed without reading the code sheet)

Photo output by php file name

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