Trying to make a primitive clicker using awt.Robot. I do not understand how to handle the event when you press the space bar, so that a click would happen. Here is the test code:

public class Main extends Application { Stage window; Robot robot; Scene scene; public static void main(String[] args) { launch(args); } @Override public void start(Stage primaryStage) throws Exception { window = primaryStage; window.setTitle("Кликер"); StackPane layout = new StackPane(); robot = new Robot(); scene = new Scene(layout, 200, 100); window.setScene(scene); window.show(); } public void keyPressed(KeyEvent e) { if (e.getKeyCode() == KeyEvent.VK_SPACE) { for (int i = 0; i < 3; i++) { robot.mousePress(InputEvent.BUTTON1_MASK); robot.delay(300); robot.mouseRelease(InputEvent.BUTTON1_MASK); robot.delay(300); } } } }

    1 answer 1

    To listen to pressing a certain button in JavaFX, you need to use the javafx.scene.input.KeyEvent library:

     import javafx.application.Application; import javafx.event.EventHandler; import javafx.scene.Scene; import javafx.scene.layout.StackPane; import javafx.stage.Stage; import javafx.scene.input.KeyEvent; import java.awt.Robot; import java.awt.event.InputEvent; public class Main extends Application { Stage window; Robot robot; Scene scene; public static void main(String[] args) { launch(args); } @Override public void start(Stage primaryStage) throws Exception { window = primaryStage; window.setTitle("Кликер"); StackPane layout = new StackPane(); robot = new Robot(); scene = new Scene(layout, 200, 100); window.setScene(scene); window.show(); scene.setOnKeyTyped(new EventHandler<KeyEvent>() { public void handle(KeyEvent ke) { if (ke.getCharacter().equals(" ")) for (int i = 0; i < 3; i++) { robot.mousePress(InputEvent.BUTTON1_MASK); robot.delay(300); robot.mouseRelease(InputEvent.BUTTON1_MASK); robot.delay(300); } } }); } }

    You cannot catch action buttons like this (such as Ctrl, Shift, function buttons, etc.). But setOnKeyPressed and setOnKeyReleased will catch them too. So, freely replace this line.

     scene.setOnKeyTyped(new EventHandler<KeyEvent>() {

    On this

     scene.setOnKeyPressed(new EventHandler<KeyEvent>() {

    or this

     scene.setOnKeyReleased(new EventHandler<KeyEvent>() {

    A touch test is replaced by this line

     if (ke.getCode().getName().equals("F12"))

    Do not depend on the platform layout or keyboard layout. They are generated when a character is entered. In the simplest case of a single key press (eg, 'a'). It can be many--may may Of Of Of Of eg eg eg eg. It is not always necessary to generate a key typed event (eg, entering ASCII sequences via Windows Alt-Numpad method). No key typed events are generated (eg, action keys, modifier keys, etc.).

    Official documentation.

    Judging by your implementation, you tried to implement the KeyListener interface's KeyListener interface. But even in this case, you would have to do Override on all its 3 methods keyPressed , keyReleased , keyTyped .

    • Yes, you did exactly what I wanted. But now, instead of a space you need to specify the F12 button. How to do it? If I write here if (ke.getCharacter (). Equals ("F12")) it does not work. Tried another unicode, but also failed. - Vladislav
    • Thank you very much. - Vladislav
    • Are you on the toaster? I asked this question in the same place, if you write this answer there, I will put it the best - Vladislav
    • @ Vladislav, I practically do not appear there. But thanks for the offer. :) - LEQADA