We need a formula for finding the current position of the horizontal damped spring pendulum. In the form of an algorithm.

Closed due to the fact that it is necessary to reformulate the question so that you can give an objectively correct answer to the participants Saidolim , cyadvert , Abyx , Athari , VladD 17 Dec '15 at 16:09 .

The question gives rise to endless debates and discussions based not on knowledge, but on opinions. To get an answer, rephrase your question so that it can be given an unambiguously correct answer, or delete the question altogether. If the question can be reformulated according to the rules set out in the certificate , edit it .

  • This physics see - Hooke's law. - cpp_user
  • I'm wildly sorry, but can I explain to those who are in the tank, and can not in physics? - user64675
  • And what is there to explain? Everything is obvious! - cpp_user
  • Um, well, for example, Wikipedia gives either a thin tensile rod formula (F = k∆l), which is not right. Or tensors and other horror. - user64675
  • I also apologize wildly, but asking for help in physics on the programmers' forum is a double way. - VladD

1 answer 1

Google: damped vibrations.

As usual, no one here will offer you a ready-made solution.

Your formula:

<script src="http://cdn.mathjax.org/mathjax/latest/MathJax.js?config=TeX-AMS_HTML-full"></script> <script type="text/x-mathjax-config"> MathJax.Hub.Config({"HTML-CSS": { preferredFont: "TeX", availableFonts:["STIX","TeX"], linebreaks: { automatic:true }, EqnChunk:(MathJax.Hub.Browser.isMobile ? 10 : 50) }, tex2jax: { inlineMath: [ ["$", "$"]], displayMath: [["$$","$$"]], processEscapes: true, ignoreClass: "tex2jax_ignore|dno" }, TeX: { noUndefined: { attributes: { mathcolor: "red", mathbackground: "#FFEEEE", mathsize: "90%" } }, Macros: { href: "{}" } }, messageStyle: "none" }); </script> $$ x = A_0 e^{-\beta t} \cos(\omega t - \phi_0) $$

For details on link 2

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