there is a pointer *N ; N="it's a good weather today"; char A[100]; How to assign the value of A N or just how to display N on the console?

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    Show me an example code, but nothing is clear - Abyx

1 answer 1

If you have a pointer that addresses a string literal

 char *N; N = "it's a good weather today";

and character array

 char A[100];

To copy a string literal into a character array, you should use the standard C function strcpy , declared in the header of <string.h> . For example,

 #include <string.h> //... strcpy( A, N );

provided that the array is large enough to hold a string literal in it. Otherwise, use the strncpy function.

 #include <string.h> //... strncpy( A, N, sizeof( A ) ); A[sizeof( A ) - 1] = '\0';

After that, you can output a string to the console, such as

 puts( A );

or

 printf( "%s\n", A );