Attempting to use std::enable_if_t in the template parameters gives an error
doesn’t name a type
, although type_traits connected, standard 11. What could be the problem?
kirill kirill
31 2
- If you are given an exhaustive answer, mark it as correct (a daw opposite the selected answer). - Nicolas Chabanovsky ♦
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1 answer
std::enable_if_t is from C ++ 14, in C ++ 11 there is only std::enable_if<C, T>::type
However, enable_if_t is an alias and you can write it yourself:
template<bool C, class T = void> using enable_if_t = typename std::enable_if<C, T>::type; 
Abyx abyx
23.5k 6 67 134
- And how can the equivalent be replaced? - kirill
- @kirill enable_if is the equivalent. - Abyx
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