Regular expression - a word of letters and numbers

Question

In line

"Теоретики3 и 2п4423рактики палинд4442рома выделили 2многочис2ленные4 погран24ичные2 с пал24инд4ром4м формы"

find words consisting of numbers and letters.

I can not write a regular expression for the job, it just happened:

 ([a-zA-Zа-яА-ЯёЁ]+\d+[a-zA-Zа-яА-ЯёЁ]+)|(\d+[a-zA-Zа-яА-ЯёЁ]+)|([a-zA-Zа-яА-ЯёЁ]+\d+)

But then the word пал24инд4ром4м divided into three, and the погран24ичные2 not completely distinguished.

Obviously, it is necessary to bind to the edge of the word \ b ... \ b

Tunker tunker 1,732 one 6 12 · Accepted Answer · 2016-04-03T15:21:49

 ((([a-zA-Zа-яА-ЯёЁ]+\d+)|(\d+[a-zA-Zа-яА-ЯёЁ]+))[a-zA-Zа-яА-ЯёЁ\d]*)

those. ((one or more letters, then one or more numbers) or (one or more numbers, then one or more letters)) then letters or numbers

Answer 2 · 2016-04-11T12:11:44

Regular this (you must set the flag to ignore the register):

 (?=\w*(?!\d)\w)(?=\w*\d)\w+

Without underscores:

 \b(?=\w*(?!\d)\w)(?=\w*\d)(?=((?!_)\w)+\b)\w+

By the way, no binding to languages :)

http://ideone.com/ZdG7Sa
http://ideone.com/sIsUF4

 using System; using System.Text.RegularExpressions; public class Test { public static void Main() { var str = "Теоретики3 и 2п4423ра_ктики палинд4442рома выделили\n" + "2многочис2ленные4 погран24ичные2 с пал24и_нд4ром4м формы"; foreach (Match match in Regex.Matches(str, @"(?=\w*(?!\d)\w)(?=\w*\d)\w+", RegexOptions.IgnoreCase)) Console.WriteLine(match.Value); Console.WriteLine("==="); foreach (Match match in Regex.Matches(str, @"\b(?=\w*(?!\d)\w)(?=\w*\d)(?=((?!_)\w)+\b)\w+", RegexOptions.IgnoreCase)) Console.WriteLine(match.Value); } }

It will not work, because you need a word of letters and numbers, and the character '_' is still in \ w.

Regular expression - a word of letters and numbers

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