Math.random().toFixed(20) allows you to generate a random number from 0 to 1 with 20 digits after the decimal point. And how can I generate random numbers with a large number of digits? After all, toFixed a maximum of 20 digits. For example, I need a random number generator with 30 digits after the decimal point.
Thisman
9,394 one 15 thirty
nonam3 nonam3
37 3
- Specify, why do you need a random number generator with 30 digits after the decimal point? - Kromster
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2 answers
The type float stores 20 decimal places. If you need 30 characters, you can get in the form of a string like this:
Math.random().toFixed(20) + Math.random().toFixed(10).substring(2) // "0.121046188135246923782935929242" But when converting to float, there will still be 20 characters:
parseFloat(Math.random().toFixed(20) + Math.random().toFixed(10).substring(2)) // "0.12104618813524692378" 
jekaby jekaby
2.574 four 18
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Add the parts after the comma as a string, and put 0 in the beginning.
Sanu
1,180 6 17
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