php: regular expression for preg_split ()

Question

I am writing a regular expression for preg_split () so that the line is broken down by spaces + with all possible punctuation marks. While it looks like this:

$pattern = "/[\s,;.\!\-\?\:\(\)]+/";

How to add a long dash to the expression, all possible quotes, etc. (maybe I forgot some other punctuation marks)?
preg_split() with such an expression adds an empty element to the end of the array. It is clear that it can be cut later, but I do not like this decision. How to correct expression so that there is no empty element?

Thank!

Answer 1 · 2016-06-02T15:55:22

1. You must decide what exactly the result is needed. If only the punctuation marks, then you have to completely list in the character class all the desired characters, including the длинное тире, все возможные кавычки и т.д. - there is no universal character class to describe this.
2. If you want to achieve a result in which it is divided into all literals that are not spaces and letters, then there is a character class [:punct:] . In regular expression, it will look like this:
```
 /[\s[:punct:]]+/ 
```
To exclude empty elements, it suffices to pass the PREG_SPLIT_NO_EMPTY flag to the preg_split function.
```
 preg_split( "/[\s[:punct:]]+/", $text, -1, PREG_SPLIT_NO_EMPTY ) 
```
http://ideone.com/iZjYU0

/ [\ s [: punct:]] + / does not work, alas ((returns the whole string as it is

php: regular expression for preg_split ()

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