There is a format string "123,456,123,23,789,67" . 6 numbers separated by commas. It is necessary to get the last 2 numbers into variables of type int .
The problem is solved easily with sscanf() :
#include <stdio.h> int main(int argc, char* argv[]) { char buf[] = "123,456,123,23,789,67"; int a1, a2, a3, a4, a5, p1, p2; sscanf(buf, "%d,%d,%d,%d,%d,%d", &a1, &a2, &a3, &a4, &p1, &p2); return 0; } Question: How to solve this problem using iterators and string class methods?
For starters, you can break a string into substrings. Options for the implementation of this (in fact - the method of split ) - the car and a small truck. Let me give you one, quite primitive, for example:
#include <sstream> #include <string> #include <vector> std::vector<std::string> split(std::string & s, char delimeter) { std::stringstream ss(s); std::string item; std::vector<std::string> tokens; while (std::getline(ss, item, delimeter)) { tokens.push_back(item); } return tokens; } Respectively,
std::string s("123,456,123,23,789,67"); std::vector<std::string> tokens = split(s, ','); Well, what to do with the resulting vector is already creative :)
std::vector can better std::forward_list ? - sys_devIf you want to get the last few numbers, then it is logical to read from the end, so as not to process potentially unnecessary data.
#include <string> #include <iostream> int main() { const std::string buf = "123,456,123,23,789,67"; size_t ppos = std::string::npos; do { size_t pos = buf.find_last_of(',', ppos - 1); int v = stoi(buf.substr(pos + 1, ppos - (pos + 1))); std::cout << v << "\n"; // 袠褋锌芯谢褜蟹褍械屑 `v` 锌芯 薪邪蟹薪邪褔械薪懈褞 ppos = pos; } while( ppos != std::string::npos ); } After obtaining the necessary amount of data, the cycle can be interrupted.
stoi() is starting with C ++ 11 - avpgnu++98 gnu++03 GNU dialect of -std=c++98. This is the default for C++ code. gnu++98 gnu++03 GNU dialect of -std=c++98. This is the default for C++ code. So even the 11th, it will not be very urgent everywhere. - avpc++11 at all, then there would be a different conversation. - 伪位蔚蠂慰位蠀蟿Source: https://ru.stackoverflow.com/questions/532825/
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