Activity.java available

@Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); final TextView textView = (TextView)findViewById(R.id.textView); // this is the view on which you will listen for touch events final View touchView = findViewById(R.id.ll); touchView.setOnTouchListener(new View.OnTouchListener() { @Override public boolean onTouch(View v, MotionEvent event) { textView.setText("Touch coordinates : " + String.valueOf(event.getX()) + "x" + String.valueOf(event.getY())); return true; } }); }

layout / activity_main.xml

 <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="fill_parent" android:id="@+id/ll" android:orientation="vertical"> <Button android:layout_width="match_parent" android:layout_height="wrap_content" android:text="New Button" android:id="@+id/button" android:layout_weight="0.50" /> <TextView android:layout_width="match_parent" android:layout_height="wrap_content" android:text="New Text" android:id="@+id/textView2" android:layout_weight="0.50" /> <TextView android:id="@+id/textView" android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="Hello World, TestActivity" /> </LinearLayout>

How to handle a touch (in this case, show the coordinates), also on the @+id/button ?

  • Set setOnTouchListener for your layout - whalemare
  • And what did I do? - ilw
  • I did not look at your code and immediately answered the question in the title. Rephrase then. Try separating button and root layout. So you will have: root layout, button and one more layout with the rest of the content. So you can separate the logic by pressing the layout and button separately. - whalemare
  • I do not want to separate anything :) This is a test layout specially created for this question and nothing else, in order to get a specific answer ... - ilw

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