gulp-replace for multiple lines?

Question

How can I register a pipe for gulp-replace for several js in gulpfile.js ?

In index.html :

 <script src="js/main.js"></script> <script src="js/plagin-1.js"></script> <script src="js/plagin-2.js"></script>

In gulpfile.js now:

 .pipe(replace('main.js', assets['main.js']))

How to make a replacement for all js files, and not for one main.js?

If simple, add .pipe(replace('plagin-1.js', assets['plagin-1.js'])) and .pipe(replace('plagin-2.js', assets['plagin-2.js'])) (if there are many files, then of course you need a more automated way).
I wanted to know more about the more automated one, but apparently there isn’t for this plug-in)
You can try this plugin npmjs.com/package/gulp-replace-assets , it accepts an object in which the keys are the replaced strings, and the values are the replacement strings.
You can throw a star here github.com/vladimirgamalian/gulp-replace-assets if it helped)

lexxl lexxl 5,051 2 gold marks 14 silver marks 35 bronze marks · Answer 1 · 2016-07-08T14:35:51

You can use regular expressions. For example, like this:

 .pipe(replace(/(.{4,8})\.js/g, 'foo'))

Where:
.{4,8} - any character from 4 to 8 times in the name
\. - point
js - the letters "j" and "s" in the extension

More information on the link: gulp-replace

1 answer 1