Good day. There is a button to switch the page loading via the Jsoup parser. If the button is pressed many times, a queue is formed and Jsoup as each download yields each result of a click. Required: if the button is pressed frequently (for example, more often 1p in 1 second), then the event does not work. If it is pressed and 1 second has passed, the event is triggered. Please tell me how this can be implemented. Thank.

    3 answers 3

    An example of the implementation of pressing the "back" button.

    In the class variable, declare private long back_pressed;

    Then, create a click capture:

      @Override public void onBackPressed() { if (back_pressed + 2000 > System.currentTimeMillis()) { stopAllServices(); finish(); } else { Toast.makeText(MainActivity.this, "Чтобы выйти, нажмите на кнопку НАЗАД ещё раз.", Toast.LENGTH_LONG).show(); back_pressed = System.currentTimeMillis(); } }

    Hope this helps you. Good luck!

      1. get a long variable in which the timeStamp last click will be stored.
      2. When pressed, compare the current time with the value of this variable.
      3. If the difference is greater than 1000ms, then complete the request, otherwise do nothing.
      4. Immediately after calculating the time difference, update the value of the variable from item 1 with the current time

        for example:

         long prevTime = 0; private void sumbmit() { long currentTime = System.currentTimeMillis(); boolean isAction = false; synchronized (this) { if (currentTime - prevTime > TimeUnit.SECONDS.toMillis(10)) { prevTime = currentTime; isAction = true; } } if (isAction) { //что то там } }
        • Chet does not want to work. TimeUnit.SECONDS.toMillis(10) , 10 is it in ms? - Pollux
        • 10 seconds in milliseconds. - Artem Konovalov