I work with the library PhpMorhpy. Attached is the following initialization example:
require_once(dirname(__FILE__) . '/../src/common.php'); // set some options $opts = array( // storage type, follow types supported // PHPMORPHY_STORAGE_FILE - use file operations(fread, fseek) for dictionary access, this is very slow... // PHPMORPHY_STORAGE_SHM - load dictionary in shared memory(using shmop php extension), this is preferred mode // PHPMORPHY_STORAGE_MEM - load dict to memory each time when phpMorphy intialized, this useful when shmop ext. not activated. Speed same as for PHPMORPHY_STORAGE_SHM type 'storage' => PHPMORPHY_STORAGE_FILE, // Extend graminfo for getAllFormsWithGramInfo method call 'with_gramtab' => false, // Enable prediction by suffix 'predict_by_suffix' => true, // Enable prediction by prefix 'predict_by_db' => true ); // Path to directory where dictionaries located $dir = dirname(__FILE__) . '/phpmorphy-0.3.7/dicts'; // Create descriptor for dictionary located in $dir directory with russian language $dict_bundle = new phpMorphy_FilesBundle($dir, 'rus'); // Create phpMorphy instance try { $morphy = new phpMorphy($dict_bundle, $opts); } catch(phpMorphy_Exception $e) { die('Error occured while creating phpMorphy instance: ' . $e->getMessage()); }
I am writing my own class that works with PhpMorphy. Earlier, I performed this initialization at the beginning of each class function. I understand that this is not correct, so I want to optimize the operation of the code. How to correctly initialize phpMorphy inside a class?
Thanks for the help!