WPF Control Style

Question

The third day I fight. Wrote the trigger for the button:

Style x:Key="SearchButtonStyle" TargetType="Button"> <Style.Triggers> <Trigger Property="IsPressed" Value="True"> <Setter Property="Content" Value="Остановить поиск"></Setter> </Trigger> </Style.Triggers> </Style>

I use:

 <Button Name="FindApp" Content="Найти приложения" Grid.Column="0" Grid.Row="3" Click="FindApp_Click" Style="{StaticResource SearchButtonStyle}"/>

No reaction.

What can be wrong?

I set Content in Style:

 <Style x:Key="SearchButtonStyle" TargetType="{x:Type Button}"> <Setter Property="Tag" Value="true"/> <Setter Property="Content" Value="Найти приложения"/> <Style.Triggers> <Trigger Property="Tag" Value="false"> <Setter Property="Content" Value="Остановить поиск"></Setter> </Trigger> <Trigger Property="Tag" Value="true"> <Setter Property="Content" Value="Найти приложения"></Setter> </Trigger> </Style.Triggers> </Style> <Button x:Name="FindApp" Grid.Column="0" Grid.Row="3" Click="FindApp_Click" Style="{StaticResource SearchButtonStyle}"/>

Vlad Vlad 2,769 one ten 28 · Answer 1 · 2016-09-06T11:49:21

Initial Content must also be set via the style:

 <Grid> <Grid.Resources> <Style x:Key="FindAppButtonStyle" TargetType="{x:Type Button}"> <Setter Property="Content" Value="Найти приложения"/> <Style.Triggers> <Trigger Property="IsPressed" Value="True"> <Setter Property="Content" Value="Остановить поиск"/> </Trigger> </Style.Triggers> </Style> </Grid.Resources> <Button Style="{StaticResource FindAppButtonStyle}"/> </Grid>

Did you remove Content="Найти приложения" from your XAML?
Yes, I changed the trigger a little, but the essence has not changed, now I’ll throw the code.
@ Sergey: For Tag does not work, because its type is object , not bool , so your Property="Tag" Value="true" value Property="Tag" Value="true" value was interpreted as the string "true" , not the value.
Try to do exactly as recommended by the author of the answer.

WPF Control Style

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