How to declare a SLOT as a parameter of a class method? (in QT5)

Question

but so as to use the syntax of the function pointer as in QObject :: connect in the QT5 version, and not (const char *):

connect(const QObject *sender, PointerToMemberFunction signal, const QObject *receiver, PointerToMemberFunction method, Qt::ConnectionType type)

For example, I want to create a class function like this:

 class CommandHub : public QObject { Q_OBJECT public: ... //эта void connectCommand(const QString &commandId, QObject *object, PointerToMemberFunction slot); ... };

I want to call connectCommand as follows:

 CommandHub commandHub; //... commandHub.connectCommand("open", someWidget, &SomeWidget::onOpen);

That is, the question is: what to use instead of PointerToMemberFunction, so that you can substitute a pointer to the slot of the object?

Make an example of what you want to achieve, but nothing is clear.

ixSci ixSci 22k 3 33 54 · Answer 1 · 2016-09-29T08:19:52

You can write your function like this:

 template <typename Sender, typename SlotType> void connectCommand(const QString &commandId, Sender* object, SlotType slot);

KoVadim KoVadim 85.7k four 66 128 · Answer 2 · 2016-09-28T14:16:14

Everything is simple - we take the editor and see, and how this connect declared for this case

  static QMetaObject::Connection connect(const QObject *sender, const QMetaMethod &signal, const QObject *receiver, const QMetaMethod &method, Qt::ConnectionType type = Qt::AutoConnection);

That is, the slot type has the form const QMetaMethod & .

I do not know exactly what the author is asking, but this answer is definitely not to his question.
He has a new syntax question, and you have the answer with the old one.

How to declare a SLOT as a parameter of a class method? (in QT5)

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