Each time you press "enter" display the following n-values of the table after them the inscription "press" enter "", press "enter" the inscription disappears the table is displayed further by n values, and if you scroll through it to the previous n-values, then the words "click" enter "" no 
#include <stdlib.h> #include <stdio.h> int main(void) { unsigned int N; int variant,i,n; double x1,x2,delta,y,x; do { printf("Vyberit' variant obchyslennja funktsii f(x)\n"); printf("1 - za tochkamy; 2 - za krokom zminy\n"); scanf("%d",&variant); if(variant==1) { printf("Vy vybraly variant: %d\n", variant); printf("Vvedit' N, x1, x2\n"); scanf("%d%lf%lf",&N,&x1,&x2); printf("x1=%.2f x2=%.2f N=%d\n",x1,x2,N); getch(); printf("-------------------------------------------------------------------------------------------------\n"); printf("| N |\t\t\t X \t\t\t|\t\t\tF(X) \t\t\t|\n"); delta=(x2-x1)/N; for(x=x1,n=1,i=0;x<x2,n<N,i<N;x=x+delta,n++,i++) { y=(x*x*x)-3*(x*x)+4; printf("-------------------------------------------------------------------------------------------------\n"); printf("| %2d |\t\t\t%5.2f \t\t|\t\t %6.2f\t\t\t|\n",n,x,y); if((i+1)% 10 == 0) { printf("Press any key...\n"); getch(); } } printf("-------------------------------------------------------------------------------------------------\n"); } else if(variant==2) \\ не доделано { printf("Vy vybraly variant: %d", variant); } else { printf("Vash vybir ne vidpovidae vymogam!\n"); } } while ((variant!=1)&&(variant!=2)); getch(); }
printf("\b\b\b\b")can help you (for example, as many characters\bas in the textPress any key...Just remove\nfromprintf("Press any key...\n");;. - VladD