How to get habr123 from a line like https://vk.com/habr123 ?

Closed due to the fact that the question is too common for the participants rjhdby , Denis , aleksandr barakin , HamSter , Hardc0re Oct 25 '16 at 15:34 .

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    3 answers 3

    No regular expressions are needed here. Here you need to remove the first 15 characters from the source line.

       /https?:\/\/(?:www\.)?(?:m\.)?vk\.com\/([a-zA-Z\d\._-]+)/

      https?:\/\/ - this is https: // or http: //

      (?:www\.)? - optional group without feedback corresponds to www.

      (?:m\.)? - Optional group without feedback corresponds to m.

      ([a-zA-Z\d\._-]+) is the resulting group with the number 1, consisting of Latin characters, numbers, periods, underscores, and dashes, containing at least 1 character

      Test https://regex101.com/r/a2ADdh/1

      PS I don’t use contact, so I don’t know where they have it and how it is stored and called names.

        Looking for the first entry point "/" from the end and delete everything in front of it, including "/"