How to send a file via http from a console application to C #?

The file is transmitted in multipart/form-data encoding. Accordingly, it is necessary:

1. Generate a splitter (for example, Asrf456BGe4h )

2. Send header

    Content-Type: multipart/form-data; boundary=Asrf456BGe4h 

3. send request body :

    (отсутствующая преамбула) --Asrf456BGe4h Content-Disposition: form-data; name="AttachedFile1"; filename="horror-photo-1.jpg" Content-Type: image/jpeg (пустая строка) (двоичное содержимое первой фотографии) --Asrf456BGe4h-- (отсутствующий эпилог - пустая строка) 

   Pay attention to the two hyphens at the end.

And then just about a thing like a puzzle for a few hours

1. Install Fiddler
2. You send the file through the browser, from where everything works.
3. You look in fiddler what exactly went.
4. You send with your code. You look in fiddler what went.
5. You finish your code until the one you send in step 4 matches what was in 3.

It seems so:
Write file to stream:

 var file = File.ReadAllBytes(filename); var req = WebRequest.CreateHttp(url); //url - адрес сервера req.Method = WebRequestMethods.Http.Post; //Отправляете на сервер(думаю знаете как) 

an action that takes a stream of bytes must have a argument byte []
How to write the stream of bytes to the file described here:
https://stackoverflow.com/questions/6397235/write-bytes-to-file

At one time I wrote an article .Net in 1C. Asynchronous HTTP requests, Post sending several multipart / form-data files, compressing traffic using gzip, deflate, convenient parsing of sites, etc.

True there is an example on 1C but it is not particularly important.

  public async Task SendPostFile(string urlserviceapiSent) { using (var client = new System.Net.Http.HttpClient()) using (var content = new System.Net.Http.MultipartFormDataContent()) { client.BaseAddress = new System.Uri(urlserviceapiSent); var values = new System.Collections.Generic.Dictionary<String, String>() { { "Name", "name"}, { "id", "id"} }; // content.Add(new FormUrlEncodedContent(values)); foreach (var keyValuePair in values) { content.Add(new System.Net.Http.StringContent(keyValuePair.Value), keyValuePair.Key); } string fileName = @"C:/ТестXML"; var fileContent = new System.Net.Http.StreamContent(System.IO.File.OpenRead(fileName)); fileContent.Headers.ContentDisposition = new System.Net.Http.Headers.ContentDispositionHeaderValue("attachment") { FileName = System.IO.Path.GetFileName(fileName) }; content.Add(fileContent); // Вариант отправки двоичных данных из файла но более краткий var fileContent2 = new System.Net.Http.StreamContent(System.IO.File.OpenRead(fileName)); content.Add(fileContent2, "attachment", "TestXml"); var stringContent = new System.Net.Http.ByteArrayContent(Encoding.UTF8.GetBytes("Тестовая строка")); stringContent.Headers.ContentDisposition = new System.Net.Http.Headers.ContentDispositionHeaderValue("attachment") { FileName = "Строка" }; content.Add(stringContent); var requestUri = "api/values/SendFiles"; var result = await client.PostAsync(requestUri, content); var str = await result.Content.ReadAsStringAsync(); textBox.AppendText(str + Environment.NewLine); } } 

Gives out such

// This is what the sent request looks like // POST http: // localhost: 40320 / api / values ​​/ SendFiles HTTP / 1.1 // Content-Type: multipart / form-data; boundary = "9f2d525a-7383-46ab-8fc7-419d73486c02" // Host: localhost: 40320 // Content-Length: 811 // Expect: 100-continue // Connection: Keep-Alive

// - 9f2d525a-7383-46ab-8fc7-419d73486c02 // Content-Type: text / plain; charset = utf-8 // Content-Disposition: form-data; name = Name

// name // - 9f2d525a-7383-46ab-8fc7-419d73486c02 // Content-Type: text / plain; charset = utf-8 // Content-Disposition: form-data; name = id

// id // - 9f2d525a-7383-46ab-8fc7-419d73486c02 // Content-Disposition: form-data; filename = "=? utf-8? B? 0J / RgNC + 0YHRgtC + 0KHRgtGA0L7QutCw? ="; name = attachment // Content-Type: text / plain

// Test line // - 9f2d525a-7383-46ab-8fc7-419d73486c02 // Content-Disposition: form-data; filename = "=? utf-8? B? 0KLQtdGB0YJYTUw =? =" // Content-Type: application / octet-stream

// 12345 // - 9f2d525a-7383-46ab-8fc7-419d73486c02 // Content-Disposition: form-data; name = attachment; filename = TestXml; filename * = utf-8''TestXml

// 12345 // - 9f2d525a-7383-46ab-8fc7-419d73486c02--

There is also a link to the service http://pastebin.com/1kyhAdai

 [NonAction] string fileName(MultipartFileData fileData) { string fileName = fileData.Headers.ContentDisposition.FileName; if (string.IsNullOrEmpty(fileName)) { return ""; } if (fileName.StartsWith("\"") && fileName.EndsWith("\"")) { fileName = fileName.Trim('"'); } if (fileName.Contains(@"/") || fileName.Contains(@"\")) { fileName = Path.GetFileName(fileName); } return fileName; } [HttpPost] public async Task<HttpResponseMessage> SendFiles() { if (!Request.Content.IsMimeMultipartContent()) { throw new HttpResponseException(HttpStatusCode.UnsupportedMediaType); } string root = HttpContext.Current.Server.MapPath("~/App_Data"); var provider = new MultipartFormDataStreamProvider(root); try { StringBuilder sb = new StringBuilder(); // Holds the response body // Read the form data and return an async task. await Request.Content.ReadAsMultipartAsync(provider); // This illustrates how to get the form data. foreach (var key in provider.FormData.AllKeys) { foreach (var val in provider.FormData.GetValues(key)) { sb.Append(string.Format("{0}: {1}\n", key, val)); } } // This illustrates how to get the file names for uploaded files. foreach (var file in provider.FileData) { var fileInfo = new FileInfo(file.LocalFileName); sb.Append(string.Format("Uploaded file: {0} {1} ({2} bytes)\n", fileName(file), fileInfo.Name, fileInfo.Length)); } return new HttpResponseMessage() { Content = new StringContent(sb.ToString()) }; } catch (System.Exception e) { return Request.CreateErrorResponse(HttpStatusCode.InternalServerError, e); } }