Initializing multiple variables

To declare several variables and then assigning the same value to them does not constitute a problem. You can write for example

 int a, b, c, d; a = b = c = d = 0; 

However, if you want to initialize variables when they are declared, you will have to initialize each variable separately. for example

 int a = 0, b = 0, c = 0, d = 0; 

or

 int a = 0, b = a, c = a, d = a; 

A simple declaration in C ++ is defined as follows (7 Declarations)

The simple-declaration

 attribute-specifier-seqopt decl-specifier-seqopt init-declarator-listopt; 

where init-declarator-list is defined as (8 Declarators)

init-declarator-list:

 init-declarator init-declarator-list , init-declarator 

init-declarator:

 declarator initializeropt 

That is, each declarator (for simplicity: a declared identifier) ​​in the list has its own initializer.

You can use initialization from a compound object , which appeared in c ++ 17:

 #include <array> auto [a, b, c, d] = std::array<int, 4>(); 

Or, more generally, to initialize with different values:

 auto [a, b, c, d] = std::array<int, 4>{{ 1, 2, 3, 4 }}; 

Such a variant is most likely compiled by the compiler into the same code as when using the explicit manual initialization of the form:

 int a = 1; int b = 2; int c = 3; int d = 4; 

However, it seems to me easier and more correct to immediately use an array, rather than individual dissimilar variables.

You can still do something like this:

 struct vars { int a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p; vars() { ZeroMemory(this,sizeof(vars)); } };