There is a form. How to transfer it to url is understandable. How to transfer it to template tags?

After all, the form needs a URL, where to send information POST.

Need for feedback form

Closed due to the fact that it is necessary to reformulate the question so that it was possible to give an objectively correct answer by the participants HamSter , aleksandr barakin , cheops , katso , Denis Nov 7 Nov '16 at 6:44 .

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    1 answer 1

    Without submission, you will not process the form. Make a separate submission for the form and send it by AJAX or redirect after processing where necessary.

    A form can be added to the base template through its tag:

    @register.assigment_tag() def get_form(): return FormFoo()

    HTML

     {% get_form as form %} <form action={% url 'form_view' %}> {{ form }} <input type="submit"> </form>
    • Hello! It returns <callback.views.FormFoo object at 0x011AEBF0> - Romuald Shmidtelson 1:22
    • Accordingly, is this the same view we attach to urla, to which we will send and receive requests? - Romuald Shmidtelson
    • who is he? and under what conditions? view gives html or json with form processing information - waynee
    • above code. {{form}} displays <callback.views.FormFoo object at 0x011AEBF0> - Romuald Shmidtelson
    • how to handle the object that is passed to the template - Romuald Shmidtelson