number = [1,2,-5,8,-9] max = number[0] for num in number: if max < 0: print(max) max+=1 
Nicolas Chabanovsky ♦
38.1k 54 gold marks 222 silver marks 438 bronze marks
agre agre
14 3 bronze marks
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3 answers
It is possible so:
number = [1,2,-5,8,-9] lst_number = [x for x in number if x < 0] print(lst_number) If the list is not needed separately, and only its output is needed, you can do this:
print([x for x in number if x < 0]) If you just need element-wise output of negative elements, you can:
number = [1,2,-5,8,-9] for num in number: if num < 0: print(num) 
Aleksandr Balyunou Aleksandr Balyunou
166 5 bronze marks
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filter(lambda x: x<0, number) 
vadim vaduxa vadim vaduxa
5,516 7 silver marks 17 bronze marks
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number = [1,2,-5,8,-9] max = [] for num in number: if num < 0: print(num) max.append(num)) 
ExUser ExUser
one 2 bronze marks
- max can not be used if you do not need to store negative elements in the array - ExUser
- Try to write more detailed answers. I am sure the author of the question would be grateful for your expert commentary on the code above. - Nicolas Chabanovsky ♦
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