Good day. Tell me, can I iterate over the elements of the string? For example, there is a string a = 'qqqq 12qw3 12 12345', from here you need to pull out the element, which will be a number and the length of which will be more than 4 characters. It may be worth using the re module, but I cannot figure out how to set the condition for selecting an element along its length.

  • one
    Likely: \d{4,} . - Qwertiy ♦
  • You can clarify the question - what to do if there are more such numbers? - MaxU
  • need to return the first number found by the condition. If such a number is found, the iteration should be stopped. - moffire

1 answer 1

Line:

 In [56]: a = 'qqqq a987654xx321aa 12qw3 12 12345 zz 1234567'

If you need to return only the first number whose length is more than 4 characters:

 In [72]: re.search(r'\b(\d{5,})\b', a).group(0) Out[72]: '12345'

Option not using RegEx :

 In [68]: [s for s in a.split() if s.isdecimal() and len(s) > 4][0] Out[68]: '12345'

If you want to return all the numbers whose length is more than 4 characters:

 In [57]: re.findall(r'\b(\d{5,})\b', a) Out[57]: ['12345', '1234567']

or so, if you count the number 987654 present in a987654xx321aa :

 In [58]: re.findall(r'(\d{5,})', a) Out[58]: ['987654', '12345', '1234567']
  • And if it is necessary to return only the first element met by condition? - moffire
  • @moffire, use re.search() . - Visman
  • @jfs, thanks, fixed. - MaxU