How to display the time in minutes in the command line after the program has started?

  • for which operating system? - Senior Pomidor
  • Windows 7 on Visual Studio 2015 - Nick
  • @Nick The simplest thing is to use the standard C asctime function - Vlad from Moscow 2:42

3 answers 3

If you want to display the time elapsed since the launch of the program and not be afraid of translating the system clock, you can use the following code (c ++ 11 and higher):

#include <chrono> #include <thread> #include <iostream> using namespace std; auto start = chrono::steady_clock::now(); // запоминаем время начала int main() { this_thread::sleep_for(std::chrono::seconds(2)); // какая-то полезная деятельность auto current = chrono::steady_clock::now(); // время в момент проверки cout << "Work time: " << chrono::duration_cast<chrono::seconds>(current - start).count() << " sec.\n"; }

The example shows seconds so that you can see the result in the online compiler.

  • It was always interesting who the author is to such an extent, um ... a perverted record of work with time in the standard? It just breaks out of the rest of the standard ... - Harry
  • @Harry and what exactly confuses? - αλεχολυτ
  • Verbosity and mediation ... - Harry
  • @Harry, however, allows you to select any time intervals without introducing different functions for (seconds / milliseconds / nanoseconds ...), and not to use the sleep(1000000000); records sleep(1000000000); when you need to wait 1 second, and the parameter takes a value in nanoseconds. All this is based on the class std::ratio in large. - αλεχολυτ

Perceiving your question as "time elapsed after the launch of the program", I would act something like this:

 int main() { time_t start_time = time(0); ... cout << (time(0)-start_time)/60 << " минут";

If you mean something else, specify more precisely what you need.

A variable can be made global - then it is initialized even before main() :)

  • Now the main thing is that no one should touch the system clock. - αλεχολυτ
  • @alexolut Needless to say :) - Harry

The answer from the English-speaking forum link

 #include <ctime> #include <iostream> using namespace std; int main() { time_t t = time(0); // get time now struct tm * now = localtime( & t ); cout << (now->tm_year + 1900) << '-' << (now->tm_mon + 1) << '-' << now->tm_mday << endl; }