For example, I have:
a = '1' How do I find all the items in the list
lst = ['123' , '231' , '564'] who have a mark in themselves
'1' 
Stanislav Grot
1,920 6 silver marks 21 bronze marks
Bernard bernard
516 1 golden mark 6 silver marks 19 bronze marks
- In the forehead - go through the list and check for each element there is a sign or not. - Vladimir Martyanov
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2 answers
a = '1' lst = ['123' , '231' , '564'] tmp = [item for item in lst if item.find(a) != -1] print(tmp) Result ['123', '231']
Stanislav Grot Stanislav Grot
1,920 6 silver marks 21 bronze marks
- oneit is better to use
a in item(works for any collection), instead ofitem.find(a). - jfs
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[item for item in lst if a in item] # or filter(lambda item: a in item, lst) 
vadim vaduxa vadim vaduxa
5,516 7 silver marks 17 bronze marks
- if you have to use
lambda, then most likely you should use an explicit genexp instead offilter()(notefilter()does not return a list here). - jfs
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