I watched the documentation https://developer.mozilla.org/en-US/docs/Web/API/XSLTProcessor . I use the latest version of Chrome. How to feed the .xsl file specified in the function header, if you know the path to it on the server disk?

    1 answer 1

    Because the transformation will be done on the client (which I personally strongly do not recommend doing), then the XML and XSL files should be available to the client. The server can send them via http / https / WebSocket .... The XSLTProcessor.importStylesheet() method takes the Node parameter.

    Those. You need

    1. get xsl file
    2. Download it to Document
    3. Give the resulting object to the importStylesheet

    In the link provided by you there is also an example of use.

     var myXMLHTTPRequest = new XMLHttpRequest(); myXMLHTTPRequest.open("GET", "example1.xsl", false); myXMLHTTPRequest.send(null); xslStylesheet = myXMLHTTPRequest.responseXML; xsltProcessor.importStylesheet(xslStylesheet);
    • open false - fuuuuuuu - Qwertiy ♦
    • @Qwertiy the person had a specific question. Let's answer in the answer fix asynchrony, support of all browsers and error notifications of proxy servers - Anton Shchyrov
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