“Invalid indirection” error indicating array indices

Question

Here, in fact, the whole program ...

#include <conio.h> #include <stdio.h> #include <math.h> void vyvod(float*,int,int); //Скорей всего неверно что-то здесь// int vnutri(float,float); float pryamaya(float,float,float,float); void sort(float*,int,int); int main() { int i,j=0,l=0; float k,b,A[15][3],B[15][4],C[15][6],r; clrscr(); printf("Vvedite coefficienty functii y=kx+b\nk="); scanf("%f",&k);//k=10.5// printf("\nb="); scanf("%f",&b);//b=-64// FILE *file1; file1=fopen("POINTS.txt","rt"); for(i=0;i<15;i++) { A[i][0]=i+1; fscanf(file1,"%f,%f;",&A[i][1],&A[i][2]); } //Здесь всё нормально из файла считывается...// printf("Massiv D1\n N xy"); vyvod(&A[0][0],15,3); //А здесь при обращении к функции начинаются проблемы// for(i=0;i<15;i++) { l=vnutri(A[i][1],A[i][2]); if(l==1) { B[j][0]=j+1; B[j][1]=A[i][0]; B[j][2]=A[i][1]; B[j][3]=A[i][2]; j=j+1; } } printf("Massiv D2\n N2 N1 xy"); vyvod(&B[0][0],j,4); //Ну и здесь соответственно тоже аналогично...// l=0; for(i=0;i<j;i++) { r=pryamaya(B[i][2],B[i][3],k,b); if(r<=3.2) { C[l][0]=l+1; C[l][1]=B[i][0]; C[l][2]=B[i][1]; C[l][3]=B[i][2]; C[l][4]=B[i][3]; l++; } } printf("Massiv D3\n N xy"); vyvod(&C[0][0],l,6); sort(&C[0][0],l,6); vyvod(&C[0][0],l,6); getch(); fclose(file1); return(0); } void vyvod(float *A,int a,int b) //Здесь почему-то массив не передаётся ф-ции// { int i,j; FILE *file2; file2=fopen("MASSIVES.txt","at"); for(i=0;i<a;i++) { for(j=0;j<b;j++) { printf("%5.1f",A[i][j]); fprintf(file2,"%5.1f",A[i][j]); } printf("\n"); fprintf(file2,"\n"); } fclose(file2); } int vnutri(float x,float y) { int m=x; float k=0,min,max; switch(m) { case 1:max=10;min=1;break; case 2: case 3: max=9;min=1;break; case 4: case 5: case 6: max=8;min=1;break; case 7: case 8: case 9: max=7;min=1;break; case 10: case 11: case 12: max=6;min=1;break; case 13: max=4;min=1;break; case 14: max=2;min=1;break; case 15: max=0;min=0;break; } if (y>=min && y<=max) k=1; return(k); } float pryamaya(float x,float y,float k,float b) { float r; r=k*xb; y=fabs(yr); x=y/k; r=(x*y)/sqrt(pow(x,2)+pow(y,2)); return(y); } void sort(float *C,int a,int b) { int i,j,t; for(i=0;i<a-1;i++) { if(C[i][b-1]>C[i+1][b-1]) { for(j=0;j<b;j++) { t=C[i][j]; C[i][j]=C[i+1][j]; C[i+1][j]=t;} } } }

Yes, it’s very difficult to figure out your code ... But first, what’s this program to do?
And yet, the message has a C ++ label, then why do you use input and output methods since cout and cin are simpler, and the program looks clearer!?
I think it would be useful for the author of the question to get acquainted with the concept of "formatted code"
Yes, sorry, this is an ordinary SI, mixed up ... In the program, you need to extract the coordinates of points from the file, put them into a two-dimensional array, then display this array, and then change it somewhere and display it again.
There's probably a problem with passing this array to a function.

skegg skegg 21.7k one thirty 60 · Answer 1 · 2011-12-05T19:31:23

So you incorrectly transfer a two-dimensional array to a function. It is necessary to transfer so:

 void vyvod(float A[][10], int a, int b)

where 10 is a constant (written for example), indicating the length of this array dimension.

If you simply pass a pointer, then you should get an element (for example, A [m] [n]) of the array A [y] [x]:

 *(A + x*m + n)

Probably, there are other errors, but I see this at once.

unless the construction A[m][n] does not develop in *(A + x*m + n) ?
To do this, the compiler must know the base of the array, i.e.

“Invalid indirection” error indicating array indices

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