Why does the else condition hold if the if condition is met?

Question

When entering a letter that is in the word variable, according to the idea, if there is no such letter, then it should display a message, that there is no such letter .

But for some reason this message is displayed even if this letter is there, why?

If you remove the last condition, it works fine

https://jsfiddle.net/xqqbyexb/

var word = 'программа'; var answerArray = []; for (var i = 0; i < word.length; i++) { answerArray[i] = "_"; } var remainingLetters = word.length; while (remainingLetters > 0 ) { alert(answerArray.join(" ")); var guess = prompt("Угадайте букву, или нажмите Отмена для выхода из игры."); if (guess === null) { // Выходим из игрового цикла break; } else { for (var j = 0; j < word.length; j++) { if(answerArray[j] === guess){ alert('Такая буква уже есть') } else if(word[j] === guess) { answerArray[j] = guess.toLowerCase(); remainingLetters--; } else if(word[j] != guess){ alert('Такой буквы нету'); break; } } } }

Answer 1 · 2016-12-18T20:34:58

You exit the loop using break; , only when the letter that the user entered is not equal to the letter we are considering. Thus, the user must guess letters in turn, starting with the first.

For example, the hidden word is абв , and the user enters the letter а . First, we compare а and а , and since they are equal, then the first character in answerArray becomes letter а . Further, а and б compared, and they are not equal, it seems Такой буквы нету and the following letters will not be checked.

But, actually, the corrected version: https://jsfiddle.net/xqqbyexb/10/ . Now everything works, and at the end the hidden word is displayed;)

Why does the else condition hold if the if condition is met?

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