I want to get the file name on the link like this:

http://localhost:7070/file.tar.gz

I tried using the URI class, but I can not find the method necessary for this ...

3 answers 3

It can be like this

 Paths.get("http://localhost:7070/file.tar.gz").getFileName()

https://gist.github.com/anonymous/d97ab4b306d67c6fa7b5c2d3e7589108

 import java.nio.file.Path; import java.nio.file.Paths; public class Program { public static void main(String[] args) { Path path = Paths.get("http://localhost:7070/file.tar.gz"); System.out.println(path); System.out.println(path.getFileName()); } }

    The URL class has a getFile() method.

    But if you look deeper inside the URL class, you can see that the internal file object in the URL set like this:

     this.file = query == null ? path : path + "?" + query;

    That is, in fact, this is all that follows in the URL after the slash following the port. If you have the following URL: http://localhost:7070/foo/bar/file.tar.gz , getFile() will return foo/bar/file.tar.gz If you need file.tar.gz , then it remains to search for the last slash ( lastIndexOf ) and take a substring, or tie commons-io , as recommended by the link in the comment under your question.

      If special classes do not fit, then you can regular:

       [^\/]*$

      Just need to add screening as needed.