Record to the list without repetitions

Question

From the site I catch the variable name_elem_site . I can not properly make a check if the current word is not equal to the last entry in the list, then add the word . Those. comes from the site

Word1, Word3, Word1, Word2, WordN ...

I get in the log, how many fun word from ms to sec, so many times and write:

Word1, Word1, Word1, Word2, Word2, Word2, ....

And because of this, I can not then calculate how many times the word was displayed. Because Word1 seemed only once for 20 seconds, for example, it’s written in my logs that 20 values were entered.

name_elem_site = text_element_by_class_name(driver, "texttexttext") currentList = [] currentWord = currentList.append(str(name_elem_site)) if name_elem_site: for word in currentList: if word == currentWord: continue currentWord = word currentList.append(word) log.write("%s\n" % word) log.flush()

In your 3rd line, the variable currentWorld is always assigned to None, because append returns nothing.
currentList.append (str (name_elem_site)) and on the new line currentWord = currentList [-1] or currentWord = str (name_elem_site)
closely related questions: Writing a variable (?) to a file and checking for the input of the same data in a row with the previous value and Exclude the entry of the same data in a row

andy.37 andy.37 6.501 7 25 · Accepted Answer · 2016-12-21T06:57:14

Check the last item

 if currentList[-1] != word currentList.append(word)

Check for entry into the list at all

 if word not in currentList: currentList.append(word)

Record to the list without repetitions

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