Replace part of php array line

Question

Hello. On the Internet there is a cloud of examples of how to replace the values of one array with another. But nowhere (in a few hours) I didn’t find how to replace only those values that meet certain criteria in the array.

Here the array_replace or str_replace can replace the values of a single Array(0=>'odin',1=>'dva',2=>'tri'); Array(0=>'one',1=>'two',2=>'three');

But I just can not figure out how to replace only part of the line, so that something like this happens:

 // было так Array(0=>'odin',1=>'dva',2=>'tri'); // а хочу получить так Array(0=>'o(d)[i]n',1=>'(d)va',2=>'tr[i]');

Those. replace the letter i with [i] and replace the letter d with (d)

The only option I can implement is this (but I would like an option with regulars):

 foreach(Array(0=>'odin',1=>'dva',2=>'tri')as$y=>$z) { // дальше с каждым значением работать отдельно, // а после всё собирать в отдельный массив }

in any case, no matter how you look at each value, you will work separately, or the function you use will do it.
What is the problem to write in your foreach line of the form data[$y] = str_replace("d", "[d]", $z) or an analogue with regular expressions, it is not clear.

user207618 · Accepted Answer · 2017-01-09T15:59:17

Use the array_map function, Luke!

 $arr = ['odin', 'dva', 'tri']; // array_map проходится по массиву, заменяя значения на возвращённое значение $arr = array_map(function($el){ // Заменяем все d и i return preg_replace_callback("/d|i/", function($found){ return $found[0] === 'd' ? '(d)' : '[i]'; }, $el); }, $arr); var_dump($arr);

https://repl.it/FEIG/0

L. Vadim L. Vadim 3.228 one five 18 · Answer 2 · 2017-01-09T16:28:51

Use str_replace;

 $arr = Array(0=>"odin",1=>"dva",2=>"tri"); foreach ($arr as $r=>$z) { $arr[$r] = str_replace("i","[i]",$z); $arr[$r] = str_replace("d","(d)",$arr[$r]); }

Replace part of php array line

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