Tell me how to open the folder where the .exe file itself is located through the list of processes in (listView)?

Question

I get the processes like this:

Process[] Proc; void startprocess() { Proc = Process.GetProcesses(); for (int i = 0; i < Proc.Length; i++) { ListViewItem itm2 = new ListViewItem(Proc[i].ProcessName + ".exe"); if (!listView1.Items.Contains(itm2)) { this.listView1.Items.Add(itm2); } } }

Now I can not figure out how to open the folder to the lying file.

Tried to do so:

  foreach (ListViewItem item in listView1.SelectedItems) { Process.Start(new ProcessStartInfo("explorer.exe", @" /select," + item.Text)); }

But always opens the same working folder.

VladD VladD 183k sixteen 223 433 · Accepted Answer · 2017-01-15T10:41:32

You need to know the full path to the process. This is done through

 Proc[i].MainModule.FileName

With the full name, you can easily get the directory:

 Path.GetDirectoryName(Proc[i].MainModule.FileName)

Tell me how to open the folder where the .exe file itself is located through the list of processes in (listView)?

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