Hello.

I do not even know how to ask a question. The bottom line is this. I tried and try to write a function that would count how many unique numbers are in a certain number. I want the function to display as in the list below:

  • $ nb = 0; // the output should be 0
  • $ nb = 1; // the output should be 1
  • $ nb = 2; // the output should be 2
  • ...
  • $ nb = 13; // the output should be 13
  • $ nb = 14; // output should be 0 0
  • $ nb = 15; // output should be 0 1
  • $ nb = 16; // the output should be 0 2
  • ...
  • $ nb = 27; // the output should be 0 13
  • $ nb = 28; // output should be 1 0
  • $ nb = 29; // the output should be 1 1
  • $ nb = 30; // the output should be 1 2
  • ...
  • $ nb = 196; // output should be 0 0 0
  • $ nb = 197; // output should be 0 0 1
  • $ nb = 198; // output should be 0 0 2
  • ...
  • $ nb = 392; // output should be 1 0 0
  • $ nb = 393; // output should be 1 0 1
  • $ nb = 393; // the output should be 1 0 2
  • ...
  • $ nb = 2743; // the output should be 13 13 13
  • $ nb = 2744; // output should be 0 0 0 0
  • $ nb = 2745; // output should be 0 0 0 1
  • $ nb = 2746; // output should be 0 0 0 2
  • ...

And I get some kind of logical error, that when entering the number 392, 1 14 -196 is output, and at 393 1 14 -195 well, etc. And when you enter a larger and smaller number in the $nb variable, a logical error is also output. For example, when I enter the number 15, I get -0 -12 -181 . I tried to do all this dynamically, but in 5 days I practically did not move anywhere.

Here is the function itself:

 // на это число делю $count = 14; // число // минимальное возможное число при $count'е 14 может быть только 196 // максимальное возможное число при $count'е 14 может быть только 391 $nb = 391; // предыдущая так сказать граница $pr_nb = explode('.', log($numb, $count))[0]; $pr_nb = pow($count, $pr_nb); // первый остаток $balance1 = $nb - $pr_nb; // второй остаток, предпоследнее число $balance2 = explode('.', $balance1 / $count)[0]; $balance2a = explode('.', log($balance2, $count))[0]; // третий остаток, последнее число $balance3 = $balance1 - (explode('.', $balance2 * $count)[0] * explode('.', log($balance1, $count))[0]); // четвёртый остаток, это 3-я цифра с конца $balance4 = explode('.', $balance1 / (pow($count, 2)))[0]; echo '<h1 style="color:red;">['.$balance4.'] ['.$balance2.'] ['.$balance3.']</h1>';

The principle is that if the number in the $nb variable is between values ​​14 in the 2nd degree, then this number will be recorded with 3 numbers (from 0 0 0 to 13 13 13 ). If in the 3rd degree, then 4 (from 0 0 0 0 to 13 13 13 13 ), if in the 4th degree, then 5 digits (from 0 0 0 0 0 to 13 13 13 13 13 ) etc.

I know that the code is just awful. Therefore, I ask for your help.

  • one
    Well, that is, transfer the number to the 14-th number system minus one unit from the highest order ... - Akina
  • @Akina yes, something like that - dgd hsk
  • Well then, what difficulties? there is a standard function base_convert, which translates into a 14-ricky, there is also a decrement of the first byte of a string variable. - Akina

1 answer 1

Here, it looks like the result is similar to the truth, if they arrange 14-digit numbers:

 $count = 14; $nb = 2743; $tmp = base_convert($nb, 10, $count); $ch = $tmp[0]; $tmp[0] = --$ch; echo $tmp;
  • Explain to me, something I’m not catching up at all, does ddd output the way it should? - dgd hsk
  • Yep In the 14th (and more) number system, the digit d is decimal 13. - Akina
  • Got it. I think right now I will simply replace the letters with the necessary numbers separately. Thank you very much! - dgd hsk