For me, this is something super-complex, how many did not try to delve into, and could not figure out what is required of me :(, I am grateful for any help

enter image description here

  • What exactly is not clear? A multidimensional list is simply a list of lists. If for you IT is super complicated, maybe programming is simply not yours? - andy.37
  • Not mine in this case, it is an algebra. - I never understood her. - user234223

2 answers 2

Short version

import math a = lambda k,n: n*f(k)+math.sin(k)*g(n) f = lambda k: 13.4*math.sin(-1.26)*math.cos(abs(k/7.5)) g = lambda n: 2*math.sin(abs(2*n))*math.cos(2*n)-11.6*math.sin(n/0.4-1) l = [[a(k, n) for k in range(1,5)] for n in range(1,5)] for n in range(len(l)): for k in range(len(l[n])): print(l[n][k],end=" ") print() m = 1 for n in range(len(l)): for k in range(len(l[n])): if l[n][k] > 2 and l[n][k] < 10: m *= l[n][k] print(m)
  • 3.5 in range(2, 10) --> False - andy.37
  • Fixed for l[n][k] > 2 and l[n][k] < 10 - Alexander Loev
 def show(a): for r in a: print ', '.join(['{:6.3f}'.format(i) for i in r]) from math import sin, cos def f(x): return 13.4 * sin(-1.26) * cos(abs(x/7.5)) def g(x): return 2 * sin(abs(2*x)) * cos(2*x) - 11.6 * sin(x/0.4 - 1) def elem(k, n): return n * f(k) + sin(k) * g(n) def matrix(K, N): return [[elem(k+1, n+1) for k in range(K)] for n in range(N)] m = matrix(4, 4) show(m)

Formulas you have some meaningless ...

Composition:

 def prod(m, lo, hi): p = 1.0 for r in m: for i in r: if lo < i < hi: p *= i return p print prod(m, 2, 10)

But there are no elements in this range.