Extract data from json and process

Question

I am trying to collect an array of data on the three criteria "city", "country", "region". The principle of operation is as follows: consider the user's IP and substitute it in json, after parsing 2 values ("city", "country" (region unavailable)) But my code swears at array_merge. Tell me how to do this?

public static function GEO() { $ip = Route::clientIp(); $json = file_get_contents('http://geoip.nekudo.com/api/'.$ip); var_dump($json); $data = json_decode($json, true); $loc = [ 'city' => null, 'country' => null, 'region' => null ]; $location = array_merge($loc, $data); return $location; }

It turned out to parse the "city", but if you parse the country, it displays "a: 2: {s: 4:" name "; s: 6:" Russia "; s: 4:" code "; s: 2:" RU ";}" how to get "name"?

Accepted Answer · 2017-02-11T07:30:22

Try this:

 public static function GEO() { $ip = Route::clientIp(); $json = file_get_contents('http://geoip.nekudo.com/api/'.$ip); var_dump($json); $data = json_decode($json, true); $location = [ 'city' => null, 'country' => null, 'region' => null ]; $location['city'] = $data['city'] $location['country'] = $data['country']['name'] return $location; }

Or even easier:

 public static function GEO() { $ip = Route::clientIp(); $json = file_get_contents('http://geoip.nekudo.com/api/'.$ip); var_dump($json); $data = json_decode($json, true); return [ 'city' => $data['city'], 'country' => $data['country']['name'], 'region' => null ]; }

The fact is that $data['country'] does not contain a value, but another array:

 "name"=>"Russia", "code"=>"RU"

Therefore, to get to the name , you need to take an array element inside the array:

 $data['country']['name']

And I need to use this code $ location = array_merge ($ loc, $ data);
Also got out the notice "Notice: Array to string conversion"
$ loc = ['city' => null, 'country' => null, 'region' => null];
Could you send the finished method, otherwise I’m completely confused (

Extract data from json and process

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