Hello, please help, the problem is in the getline() function, which takes 2 arguments: The input stream, from which the string should be extracted and the line into which the characters from the input stream are read . There is an additional 3rd argument, but I do not use it.

My problem is that I implement my own class String and getline() course, swears at the second argument, since it is not the one it needs, but my custom one.

Could you tell me how to properly implement the getline() method with my argument?

I hope that my class is String, I implement it correctly, therefore, I do not show its code due to its size and uselessness. The problem is in the method.

The code where I use getline() :

 string str; // typedef мой класс Sring для удобства int readCount = 0; int n = atoi(num); readRecord.open(fileName); if (_access(fileName, 0) != 0) { std::cout << "Error:FILE NOT FOUND" << std::endl; exit(1); } else { while (std::getline(readRecord, str))// здесь именно моя проблема { readCount++; lines.push_back(str); }
  • Only inherit from std::basic_string or do not use the standard getline - vp_arth
  • @vp_arth is likely not to use the standard getline() , you can prompt its implementation with my argument, I can’t dig up the right Internet - Nikita Gusev
  • The function must read characters from the stream into your string before the string delimiter. - vp_arth

1 answer 1

You need to implement your function. Option one - take the standard one, read the standard line, and then assign this line to yours.

Option two - read by the symbol until you meet '\ n', and add them to your string. Also nothing complicated. True, not the most effective way, but I think it is quite suitable for ordinary applications. In principle, you can work directly with rdbuf , it is faster, but it is also more difficult to write.

Since you did not write anything about the insides of your line, I can’t give you any sketches of code.

  • Thanks for the answer, you were right, it turned out to be implemented by yourself - Nikita Gusev