mas=[] while True: for x in range(0,100): c=x**2+156*x-2000 mas.append(c) if c>=0: print(c,x) break print(mas)
  • one
    Because while True ? - YozhEzhi
  • one
    Why do you need a while loop? You exit only from the for loop and the while loop is so endless and spinning - JVic

2 answers 2

You have two cycles. Internal stops. External infinite. It should probably be something like this:

 mas=[] doLoop = True while doLoop: for x in range(0,100): c=x**2+156*x-2000 mas.append(c) if c>=0: print(c,x) doLoop = False break print(mas)
  • Thanks for the answer. I just thought that the break command terminates the while loop always. - Alexander
  • one
    @ Alexander break command interrupts only the nearest cycle, but in your case it is for - andreymal
  • I would say not the closest but the cycle in which the interrupt operator is called - JVic
  • Now I figured it out, thank you - Alexander

Why is there at all while ?

 mas=[] for x in range(0,100): c=x**2+156*x-2000 mas.append(c) if c>=0: print(c,x) break print(mas)

The result is the same.

You can use the generator:

 new_list = [x**2+156*x-2000 for x in range(0, 100) if x**2+156*x-2000 <= 0] print(new_list)

Result:

[-2000, -1843, -1684, -1523, -1360, -1195, -1028, -859, -688, -515, -340, -163]

And further. In your code, the list is:

sixteen

Judging by your condition, there should be only negative values. But since you add a value to the list before checking, it gets 16 and after that the cycle is interrupted.

Change a little code. Like this:

 mas=[] for x in range(0,100): c=x**2+156*x-2000 if c>=0: print(c,x) break else: mas.append(c) print(mas)
  • Thanks, understood, redid. - Alexander