Tell me how to make a smooth appearance of the blocks when the page loads? I tried through fadeIn (I connected the jq file to the header, created the common.js file, put the code in there)

$(window).ready(function(){ $("#bf_container").fadeIn('slow'); });

But to no avail

  • what does $(window).ready mean? ........ can still $(document).ready or $(window).load ? - Alexey Shimansky
  • This means that the windows are closed and the wind is not blowing. 8) - NeedHate

1 answer 1

Maybe the fact is that the #bf_container block #bf_container already displayed? Try to hide it and run on $(document).ready

  • Thanks, it helped. #bf_container was initially displayed. - Giperion